In the given figure, if DE || BC, AD = 2.5 cm, DB = 3.5 cm and EC = 4.2 cm, then the measure of AC is:
Show answer & explanation
Correct answer: A
Explanation
The correct answer is Option 1 i.e 7.2 cm.
| Understanding/Application |
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If a line parallel to one side of a triangle intersects the other two sides of the triangle, then the line divides these two sides proportionally. DE || BC AD/DB = AE/EC |
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⇒ 2.5/3.5 = AE/4.2 ⇒ AE = 2.5 × 4.2/3.5 ⇒ AE = 3 cm So, AC = AE + EC = 3 + 4.2 = 7.2 cm |