In the given figure, DE is parallel to BC. Angle ABC = 40 degrees. Angle ADE = 130 degrees. What is the value (in degrees) of angle BAD?

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Correct answer: C
Explanation
DE ∥ BC, ∠ABC = 40°, ∠ADE = 130°
Exterior Angle Theorem / Properties of Parallel Lines
∠BAD = ∠ADE − ∠ABC
= 130° − 40°
= 90°