In the given figure, AB is parallel to EF. ED is parallel to CB and angle APE is 60 degrees. What is the value (in degrees) of angle EQC?
Show answer & explanation
Correct answer: A
Explanation
Given:
AB ∥ EF, ED ∥ CB, ∠APE = 60°
Alternate angles formed by parallel lines are equal.
ED ∥ CB ⇒ ∠APE = ∠PBQ = 60°
AB ∥ EF ⇒ ∠PBQ = ∠EQC
⇒ ∠EQC = 60°