In the given figure, AB is parallel to CD. PQ = QR. Angle BQS = 82 degrees. What is the value (in degrees) of angle PRQ?
Show answer & explanation
Correct answer: A
Explanation
Given:
AB ∥ CD
PQ = QR
∠BQS = 82°
According to the formulas:
Corresponding angles formed by parallel lines are equal.
Base angles in an isosceles triangle are equal.
∠QPC = ∠BQS = 82°
P, R, and C lie on the same straight line.
∠QPR = 82°
PQ = QR ⇒ ∠PRQ = ∠QPR
∠PRQ = 82°