In the given figure, AB is parallel to CD. Angle PAB = 65 degrees and angle DCP = 110 degrees. What is the value (in degrees) of angle APC?
Show answer & explanation
Correct answer: C
Explanation
Given:
AB ∥ CD, ∠PAB = 65°, ∠DCP = 110°
Formula:
Interior angles of parallel lines
Sum of angles of a triangle = 180°
∠APC + 65° + (180° − 110°) = 180°
⇒ ∠APC + 65° + 70° = 180°
⇒ ∠APC = 180° − 135° = 45°