In the given figure, a square ABCD is inscribed in a quadrant ACPQ. If the AB = 16 cm, find the area of the shaded region (take π =3.14) correct to two places of decimal.

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Correct answer: D
Explanation
The correct answer is option 4 i.e. 145.92 cm2.
AB = 16 cm
Area of square = a2
Area of quadrant =
Diagonal of square =
Where, a = side of square
r = radius of quadrant
Diagonal of square ABCD = radius of quadrant APCQ = =
Now, the Area of the shaded region = Area of the quadrant - the area of square
⇒ Area of shaded region =
⇒ Area of shaded region = 3.14 × 128 - 256
⇒ Area of shaded region = 401.92 - 256
⇒ Area of shaded region = 145.92
Hence the area of the shaded region is 145.92 cm2.