SSC CGL 2022 PYQ — Question 67

SSC CGL - 02 Dec 2022 - Shift 4 • Quantitative Aptitude • Q67

In the given figure, a square ABCD is inscribed in a quadrant ACPQ. If the AB = 16 cm, find the area of the shaded region (take π =3.14) correct to two places of decimal.

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4 i.e. 145.92 cm2.

AB = 16 cm

Area of square = a2

Area of quadrant = πr24\pi r^2 \over 4

Diagonal of square = a2a\sqrt{2}

Where, a = side of square

r = radius of quadrant

Diagonal of square ABCD = radius of quadrant APCQ = a2a\sqrt{2} = 16216\sqrt{2}

Now, the Area of the shaded region = Area of the quadrant - the area of square 

⇒ Area of shaded region = π(162)24−(16)2{\pi (16\sqrt{2})^2 \over 4} - {(16)^2}

⇒ Area of shaded region = 3.14 × 128 - 256

⇒ Area of shaded region = 401.92 - 256

⇒ Area of shaded region = 145.92

Hence the area of the shaded region is 145.92 cm2.