In the given figure, 3 semicircles are drawn on three sides of triangle ABC. AB = 21 cm, BC = 28 cm and AC = 35 cm. What is the area (in cm2) of the shaded part ?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. 294
Shaded area = [Area of ΔABC + area of semicircle on AB + Area of semicircle on BC] - Area of Semicircle on AC
= Area of ΔABC + πAB2/2 + πBC2/2 - πAC2/2
= Area of ΔABC + π/2[AB2 + BC2 - AC2]
= Area of ΔABC [Since AB2 + BC2 = AC2 pythagorean triplets]
= 1/2 × 28 × 21
= 294 cm2