In the figure, AB is parallel to DE. Angle BAC = 35 degrees and angle CDE = 45 degrees. What is the value (in degrees) of angle ACD?
Show answer & explanation
Correct answer: C
Explanation
Given:
AB ∥ DE
∠BAC = 35°
∠CDE = 45°
According to the formula:
Alternate interior angles formed by parallel lines are equal.
Exterior Angle Theorem: Exterior angle = Sum of the two interior opposite angles.
AB ∥ DE ⇒ ∠CED = ∠BAC = 35°
Now, in triangle CDE:
∠ACD = ∠CDE + ∠CED
= 45° + 35°
= 80°