SSC CHSL 2020 PYQ — Question 66

SSC CHSL - 15th October 2020 - Shift 1 • Quantitative Aptitude • Q66

In Δ PQR, the side QR is extended to S such that RS = PR. If ∠QPS = 110o and ∠PRQ = 70o , then the value of ∠PQR is:

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4 i.e 35o

Understanding

Tricks

Application

According to qeustion

Here 

∠PSR = ∠SPR (since RS = PR)

And 

∠PSR + ∠SPR = ∠PRQ (Exterior Angle)

Now let

∠PSR = x

x + x = 70

x = 35

So

In ΔPAS

∠PQR + 35 + 110 = 180

∠PQR = 180 - 145

∠PQR = 35