SSC CGL 2020 PYQ — Question 53

SSC CGL - 5th March 2020 Shift 2 • Quantitative Aptitude • Q53

In ΔPQR, PQ = 24 cm and ∠Q = 58o S and T are the points on side PQ and PR, respectively, such that ∠STR = 122o and If PS = 14 cm and PT = 12 cm, then the length of RT is :

Show answer & explanation

Correct answer: B

Explanation

The correct answer is option 2 i.e 16 cm

Explanation:

∠ PTS + ∠ STR = 180o

∠ PTS = 180 - 122 = 58o

∠ P is a common angle.

Δ PQR and Δ PTS are similar triangle. SO,

(PT/PQ) = (PS/PR)

⇒ (12/24) = (14/PR)

⇒PR = 28 cm

Hence,

RT = PR - PT = 28 - 12 = 16 cm