In △ PQR, ∠P = 90º, S and T are the midpoints of sides PR and PQ, respectively. What is the value of RQ2/(QS2 + RT2)?
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. .

In △ PQR, by using Pythgoras theorem we get,
RQ2 = 22 + 22 = 8.
In △ PRT, by using Pythagoras theorem we get,
RT2 = 22 + 12 = 5.
In △ PSQ, by using Pythagoras theorem we get,
SQ2 = 12 + 22 = 5.
RQ2/(QS2 + RT2) = 8/10 = 4/5.