In how many ways can 5 people be seated in a row such that A and B are not next to each other?
Show answer & explanation
Correct answer: C
Explanation
Total arrangements of 5 people = 5! = 120
Arrangements where A and B sit together = treat as one → 4! × 2 = 48
So, not together = 120 − 48 = 72
Hence, the correct answer is option 3.