In an isosceles triangle ABC, AB = AC. D is a point inside the triangle such that ∠BAD = 20° = ∠DCB, ∠CAD = 80°. The value of ∠ABC is:
Show answer & explanation
Correct answer: D
Explanation
The correct answer is Option 4 i.e. .

Since AB = AC thus, triangle ABC is isosceles
then, ∠BAC = ∠ABC
⇒ ∠BAC = ∠BAD + ∠CAD
⇒ ∠BAC = 20° + 80°
⇒ ∠BAC = 100°
Now, In triangle ABC
⇒ ∠ABC + ∠BCA + ∠BAC = 180°
⇒ ∠ABC + ∠BCA + 100° = 180°
⇒ ∠ABC + ∠BCA = 80° [∠ABC = ∠BCA]
So,
⇒ ∠ABC + ∠ABC = 80°
⇒ 2∠ABC = 80°
⇒ ∠ABC = 40°