In an examination, the number of those who passed and the number of those who failed were in the ratio 25 : 4. If three more had appeared and the number of those who failed was 3 less than earlier, the ratio of passers to failures became 21 : 3. The total number of students who initially appeared the examination was:
Show answer & explanation
Correct answer: D
Explanation
The correct answer is option 4 i.e. 261.
Let the initial number of students who passed and failed in examination be 25x and 4x respectively.
Total number of students initially = 29x
New number of total students = 29x + 3
New number of failures = 4x - 3
New number of passing students = 29x + 3 - 4x + 3 = 25x + 6
Given,
⇒ 25x + 6 = 28x - 21
⇒ 3x = 27
⇒ x = 9
Total students initially = 29x
⇒ 29 × 9 = 261