SSC CGL 2019 PYQ — Question 63

SSC CGL Tier II - Quant 13th Sep. 19 • Quantitative Aptitude • Q63

In an examination A obtained 10% more marks than B, B obtained 20% more marks than C & C obtained 32% less marks than D. If A obtained 272 more marks than C, then find the marks obtained by B.

Show answer & explanation

Correct answer: A

Explanation

The correct answer is option 1 i.e. 1020.

Explanation:

Let D obtained 100% marks

Marks of C = 68% 

Marks of B = 120 × (68)/100 = 81.6%

Marks of A = 81.6 × (110/100) = 89.76%

Difference of marks of A & C = 272

⇒ 89.76% - 68% = 272

⇒ 21.76% = 272

⇒ 81.6% = (272/21.76) × 81.6 = 1020

So, marks of B = 1020