In an election, there were two candidates A and B. The total number of voters in the constituency was 90000 and 70% of the total votes were polled. If 60% of the polled votes were cast in favour of A, how many votes were received by B?
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. 25200
Total number of voters = 90000
Percentage of votes polled = 70%
Percentage of votes in favor of candidate A = 60%
Number of votes received by a candidate = (Percentage of votes × Total number of voters)/100
Number of votes polled = (70/100) × 90000 = 63000
Number of votes in favor of candidate A = (60/100) × 63000 = 37800
Number of votes received by candidate B = Total number of votes polled - Number of votes in favor of candidate A = 63000 - 37800 = 25200