In an election, there were three candidates: A, B and C. 10% of the eligible voters did not vote. Out of those who voted, 45% voted for A, 35% voted for B and the remaining 20% voted for C. 30% of the votes polled for A and 20% of the votes polled for B were later deemed invalid, while all the votes polled for C were deemed valid. If A got 882 more valid votes than B did, how many valid votes did C receive?
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. 5040
According to the question,
Let the total votes be 'x'
882 = (Valid votes of A) - (Valid votes of B)
⇒ 882 = (70% of 45% of 90% of x) - (80% of 35% of 90% of x)
⇒ 882 = (x × 90 × 10 × 5)/1000000 (7 × 9 - 8 × 7)
⇒ 882 = (4500x)/1000000 × (63 - 56)
⇒ 882 = (45x)/10000 × (7)
⇒ x = (882 × 10000)/(7 × 45)
⇒ x = 14 × 2000 = 28000 votes
Now, valid votes did C recieve
Votes of C = 20% of 90% of valid votes
⇒ Votes of C = 20% × 90% × 28000
⇒ Votes of C = 0.20 × 0.90 × 28000
⇒ Votes of C = 0.20 × 25200 = 5040 votes