In an election, 2% of the people enrolled in the voter list did not participate, and 500 votes were invalid. Two candidates, A and B, fought the election, and A defeated B by 200 votes. If 43% of the people enrolled in the voter list casted their votes in favor of A, then what is the total number of casted votes?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is Option 1 i.e. 2450.
Calculations:
Let the total votes be x
2% of the people enrolled in the voter list did not participate = 98% of x = 0.98x
500 votes are invalid, then total votes (0.98x - 500)
The winning candidate gets 43% of the total votes = 0.43x
Losing candidate gets = 0.43x - 200
According to the question;
⇒ 0.43x + 0.43x - 200 = 0.98x - 500
⇒ 0.86x = 0.98x - 300
⇒ 0.12x = 30000
⇒ x = 2500
Hence, the number of total casted votes = 98% of 2500 = 2450