SSC Selection Post 2022 PYQ — Question 73

The correct answer is option 2 i.e. 1.

tan A = $1 \over 2$ = $P\over B$

H² = B² + P²

H = $\sqrt5$

here, H  = Hypotaneous, B = Base, P = Perpendicular

$sinA(cosA - cosC) \over cosC(sin c - sin A)$

⇒ ${1\over \sqrt5}({2\over \sqrt5} - {1\over \sqrt5}) \over {1\over \sqrt5}({2\over \sqrt5} -{1\over \sqrt5})$ 

⇒ ${1\over \sqrt5} \times {1\over \sqrt5}\over {1\over \sqrt5} \times {1\over \sqrt5}$ = 1