In ΔABC, MN || BC, the area of quadrilateral MBCN = 130 sqcm. If AN : NC = 4 : 5, then the area of ΔMAN is:

Show answer & explanation
Correct answer: A
Explanation
The correct answer is Option 1 i.e. 32 cm2
| Application |
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Given fig:
In ΔABC & ΔAMN ∠A = ∠A (common angle) ∠ABC = ∠AMN (Corresponding angle) So ΔABC ~ ΔAMN (A-A) |
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Now, ar ΔABC/arΔAMN = (AC/AN)2 ⇒ (area of qua.MBCN + arΔAMN)/arΔAMN = (9/4)2 ⇒ (130 + arΔAMN)/arΔAMN = 81/16 ⇒ (2080 + 16 × arΔAMN) = 81 × arΔAMN ⇒ (2080) = 65 × arΔAMN |
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Hence, arΔAMN = 2080/65 = 32 |