In ΔABC, AC = 8.4 cm and BC = 14 cm. P is a point on AB such that CP = 11.2 cm and ∠ACP = ∠B. What is the length (in cm) of BP?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is Option 1 i.e 3.78.
| Understanding/Application |
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Triangle ACP ~ Triangle ABC (Angle A is common and ∠ACP = ∠B) AB/AC = BC/CP = AC/AP From first 2, we get - AB/AC = BC/CP ⇒ AB/8.4 = 14/11.2 ⇒ AB = 10.5 cm |
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From last 2, we have - BC/CP = AC/AP ⇒ 14/11.2 = 8.4/AP ⇒ AP = 6.72 cm Hence, BP = AB - AP = 10.5 - 6.72 = 3.78 cm |