SSC CGL 2020 PYQ — Question 70

SSC CGL - 3rd March 2020 Shift 2 • Quantitative Aptitude • Q70

In Δ ABC, AB = AC and AL is perpendicular to BC at L. In Δ DEF, DE = DF and DM is perpendicular to EF at M. If (area of Δ ABC) : (area of Δ DEF) = 16 : 25, then (DM + AL)/(DM - AL) is equal to:

Show answer & explanation

Correct answer: B

Explanation

The correct answer is Option 2 i.e. 9.

Explanation:

(Area of Δ ABC) : (Area of Δ DEF) = 16 : 25

By the property of a similar triangle,

(DM)2/(AL)2 = 25/16

⇒ DM/AL = 5/4

By componendo dividendo:

⇒ (DM + AL)/(DM - AL) = (5 + 4)/(5 - 4)

⇒ (DM + AL)/(DM - AL) = 9/1 = 9