In △ABC, ∠A = 60º and ∠B = 50º. If the bisector of ∠B and ∠C meet at P, then ∠BPC - ∠PCA =?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. 85º
∠BPC= 90 + 1/2 × ∠A
∠BPC = 90 + 30 = 120°
∠PBA = 1/2 × ∠B
∠PBA = 1/2 × 50 = 25°
∠PCA = 180 - 120 - 25 = 35°
Required difference = 120 - 35 = 85°.