In △ABC , ∠A = 60° and ∠B = 50°. The bisectors of ∠B and ∠C meet P. Then ∠BPC + ∠PCA = ?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. 155°.
∠C = 180° - ∠A - ∠B
∠C = 180 - 50° - 60° = 70°
∠CBP = = 25°
∠BCP = = 35°
In △BPC
∠BPC = 180° - 25° - 35° = 120°
∠PCA = ∠PCB = 35°
∠BPC + ∠PCA = 120° + 35° = 155°