In a triangle PQR, S is a point on the side QR such that PS⊥ QR, then which of the following options is true?
Show answer & explanation
Correct answer: B
Explanation
The correct answer is Option 2 i.e. PR2 + QS2 = PQ2 + SR2.
Given that, PS⊥ QR
In ΔPQR
⇒ PQ2 = PS2 + QS2
⇒ PS2 = PQ2 - QS2.....(1)
Now,
In ΔPSR
⇒ PR2 = PS2 + SR2
⇒ PS2 = PR2 - SR2.....(2)
Equating both eq 1 and eq 2 together
⇒ PQ2 - QS2 = PR2 - SR2
⇒ PR2 + QS2 = PQ2 + SR2