In a triangle PQR, point E and F are on sides PQ and PR respectively such that EF is parallel to QR. If PE = 2 cm and EQ = 3 cm, then area(PQR) : area(PEF) is equal to:
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. 25 : 4.
PQ = 2 + 3 = 5 cm.
Here it is given that EF || QR then one can say that PEF is similar to PQR.
area(PQR) : area(PEF) = (5 : 2)2
area(PQR) : area(PEF) = 25 : 4.