SSC CHSL 2023 PYQ — Question 61

SSC CHSL 2023 - 03 Aug 2023 - Shift 2 • Quantitative Aptitude • Q61

In a triangle DEF, DP is the bisector of ∠D, meeting EF at P. If DE = 14 cm, DF = 21 cm, and EF = 9 cm, find EP.

Show answer & explanation

Correct answer: A

Explanation

The correct answer is option 1 i.e. 3.6 cm.

Given that

If DE = 14 cm, DF = 21 cm, and EF = 9 cm,

Let EP be x

PF = 9 - x

According to the question

ED/DF = EP/PF

⇒ 14/21 = x/9 - x

⇒ 3x = 18 - 2x

⇒ 5x = 18

⇒ x = 18/5 = 3.6 cm