In a triangle △ABC, the ∠ABC = 90°. If sin (A) = , then cos(C) is equal to:
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Correct answer: D
Explanation
The correct answer is Option 4 i.e. .

⇒ sin (A) = = P/H = BC/AC
By Pythagoras theorem,
⇒ AC2 = AB2 + BC2
here, H = Hypotaneous, B = Base, P = Perpendicular
⇒ 22 = AB2 + 12
⇒ AB2 = 4 - 1
⇒ AB2 = 3
⇒ AB = √3
So,
⇒ cos(C) = B/H = BC/AC =