In a triangle ABC, right-angled at B, if secA = 13/5, then find the value of (1 + sinA)/(cosC).
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. 25/12.

Here,
sec A = 13/5 = H/B
⇒ AC/AB = 13/5
So, let AC = 13k and AB = 5k, considering k as their common ratio.
So, BC =
Now,
sin A = AB/AC = 12/13
cos C = BC/AC = 12/13
So,
= (1 + 12/13)/(12/13) = 25/12