In a trapezium PQRS, PQ is parallel to RS and diagonals PR…

In a trapezium PQRS, PQ is parallel to RS and diagonals PR and QS intersect at O. If PQ = 4 cm, SR = 10 cm, then what is area( $\Delta$ POQ) : area ( $\Delta$ SOR)?

Show answer & explanation

Correct answer: C

Explanation

The correct answer is option 3 i.e. 4 : 25.

In the given figure PQ || SR so one can say that,

$\Delta$ PQO ~ $\Delta$ SOR

Area of $\Delta$ PQO : Area of $\Delta$ SOR = (4\10)²

Area of $\Delta$ PQO : Area of $\Delta$ SOR = 4 : 25

SSC CGL 2021 PYQ — Question 69