In a trapezium ABCD, AB and DC are parallel sides and ∠ADC = 90°. If AB = 15 cm, CD = 40 cm and diagonal AC = 41 cm then the area of the trapezium ABCD is:
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. 247.5 cm2
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Understanding |
Application |
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Given: AB = 15 cm, CD = 40 cm and AC = 41 cm ∠ADC = 90° |
From the Pythagoras theorem: AD = √(412 – 402) = 9 cm |
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We know: Area of trapezium = 1/2 × (Sum of parallel sides) × Height |
So, Area of trapezium ABCD = 1/2 × (AB + CD) × AD = 1/2 × (15 + 40) × 9 = 1/2 × 55 × 9 = 247.5 cm2 |
