SSC CPO 2022 PYQ — Question 150

SSC CPO - 9 Nov 2022 - Shift 2 • Quantitative Aptitude • Q150

In a right triangle for an acute angle x, find sinx. It is given that tanx = 5.

Show answer & explanation

Correct answer: B

Explanation

The correct answer is Option 2 i.e. 5(26)\frac{5}{\sqrt{(26)}}.

Given, tan x = 5 and,

tan x = P/B

where, Perpendicular = P, Hypotenuse = H, Base = B

⇒ P/B = 5

⇒ P = 5, B = 1

And, sin x = P/H

Using Pythagoras Theorem, we get

⇒ H2 = P2 + B2 

⇒ H2 = 52 + 12 = 26

⇒ H = 26\sqrt26

⇒ sinx = P/H = 5(26)\frac{5}{\sqrt{(26)}}