SSC CGL 2023 PYQ — Question 68

The correct answer is option 4 i.e. $\frac{2\sqrt{(10)}}{7}$.

Hypotenuse² = Base² + Perpendicular²

We know that,

sin A = Perpendicular/Hypotenuse and

cos A = Base/Hypotenuse

According to the question;

⇒ sin A = 3/7

Now,

⇒ 7² = base² + 3²

⇒ 49 - 9 = base²

⇒ base = 2√10

Hence, cos A = 2√10/7