In a right-angled triangle ABC, where the right angle is at B, if AC = 5 and BC = 3, what is the value of sin(A)?
Show answer & explanation
Correct answer: A
Explanation
Given:
∠B = 90°
AC = 5
BC = 3
According to the formula:
sin(A) = Opposite side / Hypotenuse
Side opposite to ∠A = BC = 3
Hypotenuse = AC = 5
sin(A) = 3 / 5