SSC CGL 2024 PYQ — Question 55

SSC CGL - 18 Sep 2024 - Shift 2 • Quantitative Aptitude • Q55

In a ∆PQR, PQ = PR and PT is perpendicular to QR. If PQ = 17 cm, PT = 15 cm, then what is the measure (in cm) of QR?

Show answer & explanation

Correct answer: C

Explanation

The correct answer is option 3 i.e. 16.

 

We have an isosceles triangle PQR (PQ = PR).

PT is the altitude from P to QR, dividing QR into two equal segments.

We know PQ = 17 cm and PT = 15 cm.

We need to find the length of QR.

Since triangle PTQ is a right-angled triangle, we can use the Pythagorean theorem: PT² + TQ² = PQ²

Substitute the given values: 15² + TQ² = 17² 225 + TQ² = 289 TQ² = 64 TQ = 8 cm

Find QR:

Since PT bisects QR, we know that QR = 2 × TQ.

Substitute the value of TQ: QR = 2 × 8 QR = 16 cm

Therefore, the measure of QR is 16 cm.