In a parallelogram ABCD, if vertices are in respective order and diagonals AC and BD intersect at O, then which of the following is NOT always correct?
Show answer & explanation
Correct answer: B
Explanation
The correct answer is Option 2 i.e. ∆AOD ≅ ∆COD.
∆AOB ≅ ∆COD
AO = OC (diagonals bisect each other)
BO = OD (diagonals bisect each other)
∠AOB = ∠COD (vertically opposite angles)
⇒ By SAS: ∆AOB ≅ ∆COD (Always correct)