SSC CGL 2024 PYQ — Question 61

SSC CGL - 11 Sep 2024 - Shift 1 • Quantitative Aptitude • Q61

In a division problem, the divisor is 4 times the quotient and 2 times the remainder. If the remainder is 32, then find the dividend.

Show answer & explanation

Correct answer: A

Explanation

The correct answer is Option 1 i.e. 1056.

The remainder = 32, The divisor = 4 × quotient Or 2 × Remainder

Since the remainder r = 32, we can substitute this into the equation for the divisor:

Divisor = 2r

⇒ 2 × 32 = 64

Now,

The divisor = 4 × quotient

⇒ 64 = 4 × quotient

⇒ Quotient = 16

We know that,

Dividend = Divisor × Quotient + Remainder

Dividend = 64 × 16 + 32

⇒ 1024 + 32 = 1056

Thus, the dividend is ₹1056.