In a dihybrid cross between two heterozygous fruit flies with brown bodies and red eyes (BbEe X BbEe), what will be the probability of getting BBEE genotype?
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. 1/16.
In a dihybrid cross between two heterozygous fruit flies with brown bodies and red eyes (BbEe × BbEe), the probability of getting the BBEE genotype can be calculated using the principles of Mendelian genetics. For each gene, the probability of inheriting the BB genotype is 1/4, and for the EE genotype, it is also 1/4. Since these events are independent, the combined probability of getting BBEE is (1/4*1/4= 1/16) or 6.25%.