In a constituency, 55% of the total number of voters are males and the rest are females. If 40% of the males are illiterate and 40% of the females are literate, then by what percentage is the number of illiterate females more than that of the illiterate males (correct to one decimal place)?
Show answer & explanation
Correct answer: D
Explanation
The correct answer is option 4 i.e. 22.7%.
Let's assume the population of the constituency= 100
The total number of male = 100 × 55/100 = 55
Female = 100 - 55 = 45
The total number of illiterate male = 55 × 40/100 = 22
The total number of illiterate female = 45 × (100 - 40)/100 = 27
Required percentage = (27 - 22)/22 × 100 = 22.7%