In a constituency, 45% of the total number of voters are males and the rest are females. If 60% of the males are illiterate and 60% of the females are literate, then by what percent is the number of illiterate females more than that of literate males?
(Rounded off to 2 decimal places)
Show answer & explanation
Correct answer: D
Explanation
The correct answer is Option 4 i.e. 22.22%.
Let the total number of voters be 100
45% are males = 100 × 45/100 = 45
Illiterate males = 60% of 45 = 27
Literate males = 45 - 27 = 18
Now,
55% are females = 100 × 55/100 = 55
Literate females = 60% of 55 = 33
Illiterate females = 55 - 33 = 22
The number of illiterate females is more than that of literate males = 22 - 18 = 4
Required% = 4/18 × 100 = 22.22%
Thus, the number of illiterate females is 22.22% more than that of literate males.