In a class of 80 students, 60% participate in games and the rest do not. The average weight of the former group is 5% more than that of the latter. If the average weight of all the students is 51.5 kg, then what is the weight (in kg) of the former group?
Show answer & explanation
Correct answer: B
Explanation
Correct Answer is option 2 i.e. 52.5
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Understanding |
Application |
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Total students = 80 Average weight of all the students is 51.5 kg Since, 60% of students participated in games: Hence, 60% of 80 = 48 students participated in games And number of students did not participate in games = (80 – 48) = 32 Let the weight of 32 students be 100x Weight of 48 students = 105x |
Total weight of all the students = 80 × 51.5 = 4120 kg According to the question, 105x × 48 + 100x × 32 = 4120 ⇒ 5040x + 3200x = 4120 ⇒ 8240x = 4120 ⇒ x = 0.5 kg ∴ Weight of 48 students = 105x = 105 × 0.5 = 52.5 kg |