SSC CHSL 2019 PYQ — Question 59

SSC CHSL - 1st July 2019 - Shift 3 • Quantitative Aptitude • Q59

In a circle with centre O, AD is a diameter and AC is a chord. B is a point on AC, such that OB = 5 cm and ∠OBA = 60°. If ∠DOC = 60°, then what is the length of BC?

Show answer & explanation

Correct answer: B

Explanation

The correct answer is option 2 i.e. 5 cm

Concept

Understanding

Application

Angles opposite to the equal sides are equal.

 

Angle made at semicircle is right angle.

Given

OB = 5 cm

∠OBA = 60°

∠DOC = 60°

Since OC = OD = Radius

∠OCD = ODC = (180 – 60)/2 = 60

Now

∠BCO = ∠ACO = 90° - ∠OCD

= 90° - 60° = 30°

In ∆BOC,

External ∠OBA = ∠OCB + ∠BOC

60° = 30° + ∠BOC

∠BOC = 30°

Since, ∠BOC = ∠OCB = 30°

Then, OB = BC

Hence, BC = 5 cm.