In a circle with center O, diameter AB and a chord CD intersect each other at E. AC and AD are joined. If ∠BOC = 48° and ∠AOD = 100°, then what is the measure of ∠CEB?
Show answer & explanation
Correct answer: A
Explanation
Correct Answer is option 1 i.e. 74°
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Understanding |
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Given: ∠BOC = 48° and ∠AOD = 100°
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Application |
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From the figure: ∠BOD = 180° - 100° = 80° And ∠DOC = 80 + 48 = 128° Since OD = OC ∠ODC = ∠OCD = [180 – 128]/2 = 52/2 = 26° Now in triangle OCE, ∠CEB is the exterior angle: ∠CEB = 48 + 26 = 74° |
