In a circle with center O, AB is a diameter and CD is a chord such that ∠ABC = 34° and CD = BD. What is the measure of ∠DBC?
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. 28°

Given :
∠ABC = 34° and CD = BD
Calculations :
∠ACB = 90°
In
⇒ ∠ABC + ∠ACB + ∠ BAC = 180
⇒ 34 + 90 + ∠ BAC = 180
⇒ ∠BAC = 180 - 124
⇒ ∠BAC = 56
We know ABDC is a cyclic quadrilateral
The sum of opposite angle is 180
⇒ ∠ A + ∠ D = 180
⇒ 56 + ∠ D = 180
⇒ ∠ D = 124
CD and BD are equals such that angles opposite to these sides are also equal
In , we know
⇒ CD = BD and ∠ DBC = ∠ BCD
⇒ ∠ DBC + ∠ BCD + ∠BDC = 180
⇒ 2 ∠ DBC = 180 - 124
⇒ 2 ∠ DBC = 56
⇒ ∠ DBC = 28