In a circle, two chords AB and CD intersect each other internally at point P. If AB = 16 cm, PB = 6 cm and PD = 12 cm, then the value of PC (in cm) is equal to:
Show answer & explanation
Correct answer: D
Explanation
The correct answer is option 4 i.e. 5.
PA = AB - PB
⇒ PA = 16 - 6
⇒ PA = 10cm
According to the given question,
PA × PB = PC × PD
⇒ 10 × 6 = PC × 12
⇒ PC = 60/12
⇒ PC = 5 cm