In a circle, there are two chords, AB and CD, cross each other at point E, which is located inside the circle. Given that AE is 3 cm, EB is 2 cm, and CE is 6 cm, determine the length of ED.
Show answer & explanation
Correct answer: A
Explanation
AE = 3 cm
EB = 2 cm
CE = 6 cm
According to the formula:
AE × EB = CE × ED
3 × 2 = 6 × ED
6 = 6 × ED
ED = 1 cm