In a circle of radius 8 units, a chord of length 10 units is drawn. What is the perpendicular distance of the chord from the centre of the circle in units?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. Unit.
OM is perpendicular to chord AB.
So, AM = MB = 10/2 = 5 units
OA = OB = 8 units
In right-angle ΔOMA, OA2 = OM2 + AM2
⇒ 82 = OM2 + 52
⇒ 64 = OM2 + 25
⇒ OM2 = 64 - 25 = 39
⇒ OM = √39
Therefore, the chord's perpendicular distance from the circle's center is √39 units.