In a circle of radius 10 cm, PQ and RS are two parallel chords of lengths 16 cm and 12 cm, respectively. What is the distance between the chords, if they are on opposite sides of the centre?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is Option 1 i.e 14 cm.
| Understanding/Application |
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Radius of the circle = 10 cm In triangle OBS, OB2 + BS2 = OS2 OB2 = 102 - 62 OB2 = 100 - 36 OB2 = 64 OB = 8 cm |
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In triangle OPA, OA2 + AP2 = OP2 OA2 = 102 - 82 OA2 = 36 OA = 6 cm Distance between the parallel chords = AB = OA + OB = 6 + 8 = 14 cm |