In a circle, chords AB and CD intersect internally, at E. If CD = 16 cm, DE = 6 cm, AE = 12cm, and BE = x cm then the value of x is:
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. 5.
CE = 16 - 6 = 10.
AE × EB = CE × ED
12 × x = 10 × 6
x = 5.