In a circle, chords AB and CD intersect internally at E. If CD = 18 cm, DE = 5cm, AE = 13 cm, then the length of BE is:
Show answer & explanation
Correct answer: D
Explanation
The correct answer is option 4 i.e. 5 cm.
Given that
In a circle, chords AB and CD intersect internally at E
CD = 18 cm, DE = 5cm, AE = 13 cm,
According to the chord intersection theorem
⇒ AE × EB = CE × ED
⇒ 13 × EB = (18 - 5) × 5
⇒ EB = 5 cm